Question

If x equals to a sin theta and y equals to b tan theta prove that a square upon x square minus b square upon y square equals to 1

Answer 1

Given :

x = a sin ø

y = b tan ø

To Prove :

$\frac{ {a}^{2} }{ {x}^{2} } - \frac{ {b}^{2} }{ {y}^{2} } = 1$

Solution :

LHS = a ^2 / x ^2 - b ^2 / y ^2

= a ^2 / a ^2 sin ^2ø - b ^2 / b ^2 tan ^2ø

= 1 / sin ^2ø - 1 / tan ^2ø

= cosec ^2ø - cot ^2ø

= 1

= RHS

Hence proved ....

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Answer 2

Answer:

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