if x> 0 then show that log(1+x)>(x)/(1+x)
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Answer:
x1+x<log(1+x)<x
for all x>0 using the mean value theorem. I tried to prove the two inequalities separately.
x1+x<log(1+x)⇔x1+x−log(1+x)<0
Let
f(x)=x1+x−log(1+x).
Since
f(0)=0
and
f′(x)=1(1+x)2−11+x<0
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