Question

If x>y and z<0 , then -xz ______ -yz​

Answer 1

Step-by-step explanation:

z is negative (by question)

so answer would be >

Answer 2

Answer:

x

3

+ y

3

+ z

3

= 3xyz.

Step-by-step explanation:

x

3

+ y

3

+ z

3

=

Given,

x\ +\ y\ +\ z\ =\ 0x + y + z = 0

We know that , in the algebra,

Hence the formula is,

$$\begin{lgathered}\therefore x^3\ +\ y^3\ +\ z^3\ -\ 3xyz\ =\ \dfrac{1}{2}(x\ +\ y\ +\ z)[(x\ -\ y)^2\ +\ (y\ -\ z)^2\ +\ (z\ -\ x)^2\\\end{lgathered}$$

By substituting the value of $$(x\ +\ y\ +\ z)\ =\ 0$$ the right hand side of the above expression becomes zero. Hence the expression becomes,

$$\begin{lgathered}\therfore x^3\ +\ y^3\ +\ z^3\ -\ 3xyz\ =\ 0\\\Rightarrow x^3\ +\ y^3\ +\ z^3\ =\ 3xyz\end{lgathered}$$

Hence the required value is 3xyz.

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