Question

If x>y>0 and x+y/x-y = √2. Find x²+y²/xy.​

Answer 1

x+y/x-y = √2

or, (x+y)²/(x-y)²=2

or, {(x+y)²+(x-y)²}/{(x+y)²-(x-y)²} =(2+1)/(2-1)

or, 2(x²+y²)/4xy = 3

or, x²+y²/2xy=3

or, x²+y²/xy=6