Question

if x has poisson distribution with parameters m=1, find P[X<=1]

Answer 1

Answer:

0.7358

Step-by-step explanation:

Concept:

The probability mass function of poisson distribution is

P[X=x]=$\frac{e^{-m}{m}^x}{x!}$

x=0, 1, 2, ........

Given:

m = 1

$P[X\leq1]$

=P[X=0]+P[X=1]

$=\frac{e^{-1}{1}^0}{0!}+\frac{e^{-1}{1}^1}{1!}\\\\=e^{-1}+e^{-1}\\\\=2e^{-1}$

=2 x 0.3679

= 0.7358