if X income is 60% more than Y and Y income is 40% more than Z .
by how much percent X income is more than Z
please solve fast
50 points question
Answers
Answered by
4
Let the y's income be 100.
Then, X's income = 100 + 20% of 100
= 100 + 20/100 x 100
= Rs. 120
Change in income = 120 - 100
= Rs. 20
Change percentage = change/original value x 100%
= 20/120 x 100
= 10/3 x 5
= 15/3 = 5%
Hence, 5% is y's income less than x.
Step-by-step explanation:
avinashsingh48:
maine ye nhi pucha hai
Answered by
0
X=1.6Y=1 3/5Y=8/5Y
5/8X=Y
Y=.60Z=3/5Z
Y=Y
5/8X=3/5Z
X=3/5Z×8/5
X/Z=24/25
(X/Z×100)
From above, X/Z=24/25
(24/25×4/4×100)=(96/100)×100)=96 percent
X is 96 percent of Z
HOPE IT HELPS YOU !!
Similar questions