Question

if x is 10% loss by y then y is more than x by what percentage % . ​

Answer 1

$\huge \bold \orange{question}$

if x is 10% loss by y then y is more than x by what percentage % .

$\huge \bold \orange{answer}$

According to the question ,

x is 10% more than y

so,

$x = \frac{y + 10}{100 \times y} \\ x = \frac{11y}{10} \\ x = 1.1y \\ as \: y \: is \: \: less \: than \: x \\ = \frac{0.1}{1 \times 100} \\ = 10 \%$