if x is 2 + root 5 prove that x ^2 + 1 upon x ^2 is equals 18
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Answer:
10-4√5
Step-by-step explanation:
x^2 = (2 +√5)^2
=4 + 5 + 4√5
= 9 +4√5
1 / x^2 = 1/(9+ 4√5)
= (9-4√5) / 81- 80
= 9-4√5
(x^2 +1) / (x^2)
= x^2/ x^2 + 1 /x^2
= 1 + 1/x^2
= 1 + 9 -4√5
= 10-4√5
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