if X is 30percnt more than y then find y+x/x
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Answer:
Let y = a
Then x = a × (100 + 30)/100
= a × 130/100
= 13/10 a
Now, (i) x/y = (a/13)/10a
= (a × 10)/13a
= 10/13
(ii) (y + x)/x = (a + 13/10.a)/(13/10.a)
= (10 + 13)a/(10 × 13/10.a )
= 23a/10 × 10/13a = 23/13
(iii) y/(y – x) = a/(a – 13/10.a)
= (a/-3)/10.a
= (a × 10)/(-3a)
= -10/3
Answered by
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Step-by-step explanation:
(i) Let y = a
Then x = a × (100 + 30)/100
= a × 130/100
= 13/10 a
Now, (i) x/y = (a/13)/10a
= (a × 10)/13a
= 10/13
(ii) (y + x)/x = (a + 13/10.a)/(13/10.a)
= (10 + 13)a/(10 × 13/10.a )
= 23a/10 × 10/13a = 23/13
(iii) y/(y – x) = a/(a – 13/10.a)
= (a/-3)/10.a
= (a × 10)/(-3a)
= -10/3
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