Math, asked by tcmohuamaity, 3 months ago

if X is 30percnt more than y then find y+x/x

Answers

Answered by prabhat311
0

Answer:

 Let y = a

Then x = a × (100 + 30)/100

= a × 130/100

= 13/10 a

Now, (i) x/y = (a/13)/10a

=  (a × 10)/13a

= 10/13

(ii) (y + x)/x = (a + 13/10.a)/(13/10.a)

= (10 + 13)a/(10 × 13/10.a )

= 23a/10 × 10/13a = 23/13

(iii) y/(y – x) = a/(a – 13/10.a)

= (a/-3)/10.a

= (a × 10)/(-3a)

= -10/3

Answered by vinayakchindi
0

Step-by-step explanation:

(i) Let y = a

Then x = a × (100 + 30)/100

= a × 130/100

= 13/10 a

Now, (i) x/y = (a/13)/10a

= (a × 10)/13a

= 10/13

(ii) (y + x)/x = (a + 13/10.a)/(13/10.a)

= (10 + 13)a/(10 × 13/10.a )

= 23a/10 × 10/13a = 23/13

(iii) y/(y – x) = a/(a – 13/10.a)

= (a/-3)/10.a

= (a × 10)/(-3a)

= -10/3

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