Question

If x is 4/5 then find,


3x/4 - (x - 4)/3​

Answer 1

Answer:

101/60

Step-by-step explanation:

x=4/5

{3×4/5×5}-(3/4-4)/3

12/20+13/12

36+65/60

101/60

Answer 2

Answer:

3x)/4-[(x-4)/3)] = 5/3

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0⇒9x-4*x+16-20=0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0⇒9x-4*x+16-20=0⇒5x-20+16 = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0⇒9x-4*x+16-20=0⇒5x-20+16 = 0⇒5x-4 = 0

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0⇒9x-4*x+16-20=0⇒5x-20+16 = 0⇒5x-4 = 0⇒5x=4

3x)/4-[(x-4)/3)] = 5/3⇒(3x)/4-[(x-4)/3)]-(5/3) = 0⇒(3x)/4-[(x-4)/3)]-5/3 = 0⇒[-1(x-4)]/3+(3x)/4-5/3 = 0⇒[-1*4(x-4)]/(3*4)+(3*3x)/(3*4)+(-5*4)/(3*4) = 0⇒3*3x-1*4*(x-4)-5*4 = 0⇒9x-4*x+16-20=0⇒5x-20+16 = 0⇒5x-4 = 0⇒5x=4⇒x=4/5

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