If x is a digit of a number 265 x 32 such that 11 is divisible by 3, what will be the possible value of x
Answers
Answered by
2
The divisibility test for 11 is that:
The difference of the sums of digits in alternate positions should give zero or a number that is divisible by 11; (we can use 11 or -11)
In the number 265 x 32, the digits in alternate positions are as shown below:
265 x 32
Using 0
(2+5+3) - (6+x+2) = 0
10 - (8+x) = -11
10 - 8 - x = 0
2-x = 0
x = 2
... and the number becomes
265232
265232/11 = 24112
The difference of the sums of digits in alternate positions should give zero or a number that is divisible by 11; (we can use 11 or -11)
In the number 265 x 32, the digits in alternate positions are as shown below:
265 x 32
Using 0
(2+5+3) - (6+x+2) = 0
10 - (8+x) = -11
10 - 8 - x = 0
2-x = 0
x = 2
... and the number becomes
265232
265232/11 = 24112
Answered by
1
Answer:
Step-by-step explanation:
The divisibility test for 11 is that:
The difference of the sums of digits in alternate positions should give zero or a number that is divisible by 11; (we can use 11 or -11)
In the number 265 x 32, the digits in alternate positions are as shown below:
265 x 32
Using 0
(2+5+3) - (6+x+2) = 0
10 - (8+x) = -11
10 - 8 - x = 0
2-x = 0
x = 2
... and the number becomes
265232
265232/11 = 24112
Similar questions