Question

*If x is a geometric mean of 16 & 4 then find value of x .*

1️⃣ 16
2️⃣ 4
3️⃣ 64
4️⃣ 8​

Answer 1

Given :- If x is a geometric mean of 16 & 4 then find value of x .*

1️⃣ 16

2️⃣ 4

3️⃣ 64

4️⃣ 8

Answer :-

we know that,

• Geometric mean of a and b = √(ab)

we have , given that,

• a = 16
• b = 4
• x = Geometric mean

so,

→ x = √(ab)

→ x = √(16 * 4)

→ x = √(64)

→ x = √(8)²

→ x = 8 (Option 4) (Ans.)

Learn more :-

evaluate the expression given by 83 - 81 + 87 - 85 +__________ + 395 - 393 + 399 - 397

https://brainly.in/question/14081691

If the nth term of an AP is (2n+5),the sum of first10 terms is

https://brainly.in/question/23676839

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If x is a geometric mean of 16 & 4 then find value of x

1. 16

2. 4

3. 64

4. 8

EVALUATION

Here it is given that

x is a geometric mean of 16 & 4

So 16 , x , 4 are in Geometric Progression

$\displaystyle \sf{ \implies \: \frac{x}{16} = \frac{4}{x} }$

$\displaystyle \sf{ \implies \: {x}^{2} = 16 \times 4}$

$\displaystyle \sf{ \implies \: {x}^{2} = 64}$

$\displaystyle \sf{ \implies \: x = 8}$

Hence the required geometric mean = 8

FINAL ANSWER

Hence the correct option is 4. 8

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. 8 GM's are inserted between 3 and 4

then the product of 8 GM's

https://brainly.in/question/29050188

2. Find the smallest term of geometric progression 3,5,25/3 that exceeds 100.

https://brainly.in/question/26328002