if x is a natural number the x+(x+1)+..........+(x+2006)is always divisible by
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x+(x+1)+....+(x+2006)
=2007x+(1+2+....+2006)
=2007x+(2006)(2007)/2
=2007(x+2006/2)
=2007(x+1003)
So this expression is always divisible by 2007.
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