If x is a negative integer such that distance between (x, 2) and (4, - 6) is 10 units, then x equals
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Answer:
the answer is x=-8 (minus 8)
The negative integer is (-8) which calculates the distance
Answered by
1
Here, we will use the Distance formulae
√[(x1 – x2) ^2 +(y1 – y2) ^2]= distance between (x1, x2) and (y1, y2)
Step-by-step explanation:
Applying the equation,
X1= x y1=2
X2=4 y2= –6
√[(x–4) ^2+(2-(-6)) ^2] = 10 (given in question)
√[ x^2+16-8x+64]=10
[x^2-8x+80]=100 (squaring on both sides)
X^2-8x-20=0
X^2-10x+2x-20=0
X(x-10) +2(x-10) =0 (Taking x common from first two expressions and 2 from last two)
(X+2) (x-10) =0
Putting both if them seprately 0
X+2=0 x–10=0
X=–2 x=10
Since given in question x is negative so,
X= –2 is the answer
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