Question

if x is a positive integer a positive integer such that the distance between points P (x, 2) and 00.-6) is 10 units, then x= (b) - 3 (c) 9 (d) -9​

Answer 1

Answer:

Distance between two points

(x2−x1)2+(y2−y1)2

(x−3)2+(2−(−6))2=10

(x−3)2+64=10

 Squaring both sides

(x−3)2+64=100

x2−6x−27=0

x2−9x+3x−27=0

x(x−9)+3(x−9)=0

x=−3,9

Taking positive value, x=9units

Answer 2

Answer:

-3,9

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