Question

if x is a positive real number and x^2=2 then find the value of x^3​

Answer 1

x is actually square root of 2 so when its cube is done its value is 2.74 approximately

Answer 2

Given,

${x}^{2} = 2 \\ \\ so \\ \\ x = ( + or - ) \sqrt{2}$

But it is given that x is positive real number. Therefore,

$x = \sqrt{2}$

Now we have to find x^3.

So,

${x}^{3} = x \times x \times x \\ \\ = \sqrt{2} \times \sqrt{2} \times \sqrt{2} \\ \\ = 2 \sqrt{2}$

Hope it helps.