If X is a random variable with E(X) = 5 and V ar(X) = 2. What is E(X2)?
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Step-by-step explanation:
Given μ = E(X) = 5 and E(X - μ)^(2) = 2 .
Now,
E(X - μ)^2 = E {X^(2) + μ^(2) - 2μX}
= E(X^2) + μ^2 - 2μ E(X) = E(X^2) - μ^2. Therefore ; E(X^2) = 2 + μ^2 = 2 + 25 = 27 .
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