If x is a whole number, then x²(x² - 1) is always divisible by ?
A) 4
B) 8
C) 12
D) None
Answers
Answered by
0
If x is a whole number, then x²(x² - 1) is always divisible by ?
A) 4
B) 8
C) 12
D) None
=>Option C
Description:
We can do this by trial and error method.
Putting x = 2,we get 2²(2² - 1) = 12.
checking with other integers, the above equation always gives a value which is a multiple of 12,
So, x²(x² - 1) is always divisible by 12.
A) 4
B) 8
C) 12
D) None
=>Option C
Description:
We can do this by trial and error method.
Putting x = 2,we get 2²(2² - 1) = 12.
checking with other integers, the above equation always gives a value which is a multiple of 12,
So, x²(x² - 1) is always divisible by 12.
Answered by
0
Heya Mate !!!
Your Answer is ; 12.
========================
Step by Step Explanation ;-
========================
This question can be solved by using trial and error method ;-
Let's Put Y = 2
Result = 2^2 (2^2-1) = 12.
Let's check with other integers ;-
Hola , the above questions is resulting the number 12.
So , y^2 ( y^2 - 1 ) seems always divisible by 12.
Hence , 12 is the right answer.
Your Answer is ; 12.
========================
Step by Step Explanation ;-
========================
This question can be solved by using trial and error method ;-
Let's Put Y = 2
Result = 2^2 (2^2-1) = 12.
Let's check with other integers ;-
Hola , the above questions is resulting the number 12.
So , y^2 ( y^2 - 1 ) seems always divisible by 12.
Hence , 12 is the right answer.
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