Question

If x = ½ is a zero of the polynomial 2x2 +kx -12,then find the value of x.​

Answer 1

${\huge{\boxed{\underline{\textbf{\textsf{\color{violet}{An}{\color{lightblue}{sw}{\color{lightgreen}{er:}}}}}}}}}$

To Solve:

• If x = ½ is a zero of the polynomial 2x2 +kx -12,then find the value of k.

Solⁿ:

$x = \frac{1}{2}$

2x² + kx - 12 = 0

Putting the value of zero X

${ \sf{2 {( \frac{1}{2} )}^{2} + k( \frac{1}{2} ) - 12 = 0}} \\ \\ { \sf{2( \frac{1}{4} ) + \frac{k}{2} - 12 = 0 }}\\ \\ { \sf{ \frac{1}{2} + \frac{k}{2} - 12 = 0}} \\ \\ { \sf{\frac{1}{2} + \frac{k}{2} = 12}} \\ \\ { \sf{\frac{1 + k}{2} = 12 }}\\ \\ { \sf{1 + k = 12 \times 2 }}\\ \\ { \sf{1 + k = 24}} \\ \\{ \sf{ k = 24 - 1}} \\ \\ \: {\color{orchid}{\boxed { \sf{k = 23}}}}$

So, k is 23.

The Polynomial :- 2x² + 23x - 12

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