Math, asked by subhammaity, 10 months ago

if x is a1000 digit. number ,y. is the sum of it's digits,z the sum of the digits of y and w the sum of the digits of z, then the maximum possible value of w is​

Answers

Answered by saisevithaaparents
2

Answer:

9

Step-by-step explanation:

a thousand digit number x

max value is if all digits are 9

y=9*1000=9000

z=9+0+0+0=9

w=9

Answered by ankurbadani84
1

Answer:

9

Step-by-step explanation:

Consider 4 digit Number - 9999 - x

y is the sum of it's digits of x  - 36 -- ( 9+9+9+9)

z the sum of the digits of y  - 9 --- (3+6)

w the sum of the digits of z - 9

Now, Let us take below scenario where we maximize y.

Consider 4 digit Number - 9002 - x

y is the sum of it's digits of x  - 11 -- ( 9+0+0+2)

z the sum of the digits of y  - 2 --- (1+1)

w the sum of the digits of z - 2

So if, we realize w will always become 1 digit number. Maximum value of that will be 9 as seen in case example with 9999. Same will be the result with 9000.

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