if x is a1000 digit. number ,y. is the sum of it's digits,z the sum of the digits of y and w the sum of the digits of z, then the maximum possible value of w is
Answers
Answered by
2
Answer:
9
Step-by-step explanation:
a thousand digit number x
max value is if all digits are 9
y=9*1000=9000
z=9+0+0+0=9
w=9
Answered by
1
Answer:
9
Step-by-step explanation:
Consider 4 digit Number - 9999 - x
y is the sum of it's digits of x - 36 -- ( 9+9+9+9)
z the sum of the digits of y - 9 --- (3+6)
w the sum of the digits of z - 9
Now, Let us take below scenario where we maximize y.
Consider 4 digit Number - 9002 - x
y is the sum of it's digits of x - 11 -- ( 9+0+0+2)
z the sum of the digits of y - 2 --- (1+1)
w the sum of the digits of z - 2
So if, we realize w will always become 1 digit number. Maximum value of that will be 9 as seen in case example with 9999. Same will be the result with 9000.
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