If x is acute,then √1+sin x /1-sin x=?
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Solution :
√(1+sinx)/(1-sinx)
= √[(1+sinx)(1+sinx)/(1-sinx)(1+sinx)]
= √[(1+sinx)²/√(1-sin²x )]
= √(1+sinx)²/√cos²x
= (1+sinx)/cosx
= 1/cosx + sinx/cosx
= secx + tanx
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