Question

if x is added to each of number 3,9,21 so that the resulting number may be in GP then the valur of x will be

Answer 1

3+x+9+x+21+x646494*44,!
acacagvahajn
55+*6666666=494@4'4,=4
a94**45'4''4'5'4'5''5'5
*5*5*56266#"5*996

Answer 2

Solution:-

according to the question,

x is add 3,9 and 21

=> (3+x) (9+x) and  (21+x)

if these are in GP

then,

(9+x)^2 =(3+x) (21+x)

=>81+18x+x^2=63+24x+x^2

(both sides x^2 available hence remove this)

=>18x-24x=63-81

=>-6x=-18x

=>x=3

Ans

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