If x is an acute angle and sin(x+28°)=cos(3x-78°)
then the angle is
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Answered by
12
Answer:
We know that sinФ=cos(90-Ф)
Thus, sin(x+28)⇒cos{90-(x+28)}⇒cos(62-x)
Thus, sin(x+28)=cos(62-x)......(1)
But, sin(x+28)=cos(3x-78)...(2)
Subtract (1) and (2). You will get:
cos(62-x)=cos(3x-78)
We can equate cos.
62-x=3x-78
62+78=3x+x
140=4x
x=140/4
x=35°
HOPE THIS HELPS :D
Answered by
0
Answer:
35 degrees
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