Question

if x is an acute angle and sin x=cos x find the value of 2sin^2x-3cos^2x+1/2 cot^2x​

Answer 1

Answer:

0

Step-by-step explanation:

Given,

Sin x = Cos x and x is acute angle.

=> x = 45° ( ∵ Sin45 = Cos45 = 1/√2)

Now,

2Sin²x - 3Cos²x + 1/2 Cot²x

= 2 * (Sin²45) - 3 (Cos²45) + 1/2(Cot²45)  

= 2 * 1/2 - 3 * 1/2 + 1/2 * 1  (∵ sin45 = cos45 = 1/√2 and Cot45 = 1)

= 1 + 1/2 - 3/2

= 3/2 - 3/2

= 0