Question

If x is an acute angle such that tan^2 x = 8/7 , then the value of (1+sin x)(1-sin x)/ (1+cos x)(1-cos x) is

Answer 1

Step-by-step explanation:

tan²x=8/7.

(1+sinx)(1-sinx)/(1+cosx)(1-cosx)

=(1-sin²x)/(1-cos²x). [(a+b)(a-b)=a²-b²]

=cos²x/sin²x. [sin²x+cos²x=1]

=cot²x. [cotx=1/tanx.]

=7/8.

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