Question

if x is an even integer and sum of 12 consecutive even numbers from x is found to be 588 then find the mean of 10 consecutive even numbers starting from X-20​

Answer 1

Here is my answer my dear friend

Answer 2

Given:

x is an even integer such that the sum of 12 consecutive even numbers starting from x is 588.

To Find:

The mean of the 10 consecutive even numbers starting from x-20 is?

Solution:

1. The given even integer is x, the sum of 12 consecutive integers starting from x is 588,

=> x +  x +2 + x +4 + x +6 + x + 8 + x + 10 + x +12 + x + 14 + x + 16 + x + 18 + x + 20 + x + 22 = 588,

=>  12x + 132 = 588,

=> 12x = 588 - 132,

=> 12x = 456,

=> x = 38.

2. The even integer is 38, The mean of 10 consecutive integers starting from x - 20 is,

=> Mean = Sum of all the obersvations / Total number of obeservations.

=> Mean = ((18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36)/10),

=> Mean = 270/10,

=> Mean = 27.

Therefore, the mean of 10 consecutive even integers starting from 18 is 27.