Question

If x is equal.t o root 2 plus 1 by root 2 minus 1 and y is rot 2 minus 1 by root 2 plus 1 फाइंड ज स्क्वेर प्लस क्षय प्लस वाई square

Answer 1

according to question
$x = \sqrt{2} + 1 \div \sqrt{2} + 1 \\ y = \sqrt{2} - 1 \div \sqrt{2} + 1 \\ so \\ x {}^{2} + y {}^{2} = (\sqrt{2} + 1 \div \sqrt {2} + 1 ) {}^{2} + ( \sqrt{2} - 1 \div \sqrt{2} + 1 ) {}^{2} \\ = (2 + 1 \div 2 + 1) + (2 - 1 \div 2 + 1) \\ = (3 \div 3) + (1 \div 3) \\ = 1 + 1 \div 3 \\ = 4 \div 3 \\ = 1.33333answer$