if x is equal to 1 and y is equal to 6 is a solution of the linear equation 8 x minus k y + k square is equal to zero then find the value of k
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Answered by
36
8x-ky+k^2=0
8×1-6k+k^2=0
k^2-6k+8=0
k^2-4k-2k+8=0
k(k-4)-2(k-4)
(k-2) (k-4)
either k=2
or k=4
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Answered by
4
Answer:
kkkkkkkkkkkkkkkkkkkkkkk
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