Question

if x is equal to 1 by 7 minus 4 root 3 and y is equals to 1 by 7 + 4 root 3 then the value of x cube+ y square​

Answer 1

Step-by-step explanation:

$x = \frac{1}{7 - 4 \sqrt{3} }$

$y = \frac{1}{7 + 4 \sqrt{3} }$

${x}^{3} + {y}^{?} = ( \frac{ {1})^{3} }{7 - 4 \sqrt{3} )} + ( { \frac{1}{7 + 4 \sqrt{3} }) }^{2}$

1/289-64x3+1/49+48

1/289-192+1/97

1/96+1/97

solve this u get urs answer perfectly

Answer 2

Answer:

check the question ,. it must be x³+y³ or x²+y²

I have solved it by x³+y³