if x is equal to 1 upon 2 root 3 is a zero polynomial p(x) is equal to 2 kx square - 7 x + k then find value of k
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Here is your answer!
x=1/2root3
=2root3/2root3×2root3
=2root3/ 12
=root3/6
p(x)=2kx^2-7x+k
Then put the value of X in the equation
p(root3/6)=2×k×(root3/6)^2-7
(root3/6)+k
=2k×3/36-7root3+k
=k/6-7root3/6+k
=k-7root3+6k/6=0
=k-7root3+6k=0×6=0
7k=7root3
k=7root3/7
k=root3
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x=1/2root3
=2root3/2root3×2root3
=2root3/ 12
=root3/6
p(x)=2kx^2-7x+k
Then put the value of X in the equation
p(root3/6)=2×k×(root3/6)^2-7
(root3/6)+k
=2k×3/36-7root3+k
=k/6-7root3/6+k
=k-7root3+6k/6=0
=k-7root3+6k=0×6=0
7k=7root3
k=7root3/7
k=root3
✓✓✓✓✓✓✓
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