if x is equal to 2 is a zero of the quadratic polynomial 2sqare -kx+6, find the value of k
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Value of x=2 put it in the polynomial
2^2-kx+6=0
2^2-k(2)+6=0
4-2k+6=0
10-2k=0
-2k= -10
K= -10/-2
K=5
Value of K =5
2^2-kx+6=0
2^2-k(2)+6=0
4-2k+6=0
10-2k=0
-2k= -10
K= -10/-2
K=5
Value of K =5
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k is 7...this can be obtained by substituting the value of 'x' as 2....
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