Math, asked by Srinivas8086, 1 year ago

If x is equal to 2+ root 5 then find xsquare +1/x squate

Answers

Answered by Anonymous
99
Heya ✋

Let see your answer !!!

Given that

x = 2 + √5

x^2 + 1/x^2 = ?

Solution

1/x = 1/2 + √5

By rationalization

= 1 × (2 - √5)/(2 + √5) × (2 - √5)

= 2 - √5/(2)^2 - (√5)^2

= 2 - √5/4 - 5

= 2 -√5/-1

= -2 + √5

Therefore ,

x^2 + 1/x^2

= (2 + √5)^2 + (-2 + √5)^2

= (2)^2 + (√5)^2 + 2 × 2 × √5 + (-2)^2 + (√5)^2 + 2 × (-2) × √5

= 4 + 5 + 4√5 + 4 + 5 - 4√5

= 9 + 4√5 + 9 - 4√5

= 18




Thanks :)))))


indianbro74: thanks to you it was little hard but it is very good
Anonymous: Ur welcome
indianbro74: thanks
indianbro74: a=7-4 root3 find the value of RootA+1 by rootA
indianbro74: please solve it
Anonymous: Ask this question in brainly there l will solve comment section is only for appreciating answers so nothing l can do here
indianbro74: okk
Answered by KBC15PIYU
46
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