Math, asked by manyachopra2701, 7 months ago

if x is equal to (3/2)^2 * (2/3)^-4 Then find the value of x^-2

Answers

Answered by Thenavi
0

Answer:

(2/3)^12

Step-by-step explanation:

x=(3/2)^2×(2/3)^-4

x=(3/2)^2×(3/2)^4

x=(3/2)^2+4

x=(3/2)^6

x^-2=[(3/2)^6]^-2

=(3/2)^-12

=(2/3)^12

Answered by naveenauday
0
X=(9/4)/(2/3)^4. (a^-m=1/a^m
X=9x81/4x16
X=9^3/4*3
X=3^6/2^6=(3/2)^6
X^-2=(3/2)^6-2
X-2=(3/2)^4
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