if x is equal to 3 is one root of the quadritic equation x square-2kx-6=0 then find value of k
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Given that x = 3 of the equation x² - 2kx - 6 = 0
Substituting the value of x in the equation to get k
3² - 2k×3 - 6 = 0
9 - 6k = 6
6k = 3
k = ½
Substituting the value of x in the equation to get k
3² - 2k×3 - 6 = 0
9 - 6k = 6
6k = 3
k = ½
VarshaKhairwal:
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Answered by
3
x^2-2kx-6=0
put x=3 in eq
3^2-2k×3-6=0
9-6k-6=0
-6k=6-9
k=-3/-6
k=1/2 is your ans hope it's help u
mark as brainliest
put x=3 in eq
3^2-2k×3-6=0
9-6k-6=0
-6k=6-9
k=-3/-6
k=1/2 is your ans hope it's help u
mark as brainliest
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