Question

if x is equal to 3 minus 2 root 2 find x cube minus one by x cube​

Answer 1

$\huge \mathfrak \red{answer}$

$\rm \blue{128 \sqrt{2}}$

❁_____________________________❁

$\bf \huge{question}$

if x is equal to 3 minus 2 root 2 find x cube minus one by x cube

$\sf{x = 3 - 2 \sqrt{2}}$

☆__________________________________☆

$\tt {step \: to \: step \: explanation}$

Given

$\tt{x = 3 - 2 \sqrt{2}}$

$\tt{ \frac{1}{x} = \frac{1}{3 - 2 \sqrt{2} }}$

then

$\tt{ = \frac{1}{3 - 2 \sqrt{2} } \times \frac{(3 + 2 \sqrt{2)} }{(3 + 2 \sqrt{2)} }}$

$= \tt{ \frac{(3 + 2 \sqrt{2)} }{ {(3}^{2} - (2 \sqrt{2 }^{2} )} }$

$\tt \red{ = 3 + 2 \sqrt{2}}$

then after according to the problem

$\tt{(x - \frac{1}{x} )}^{3}$

$= \tt{(3 - 2 \sqrt{2} - 3 - 2 \sqrt{2})}$

$= \tt{( - 4 \sqrt{2 )}^{3} }$

$\tt{ = 128 \sqrt{2}}$

______________________________

Answer:

$\bf{ \huge{ \boxed{ \green{ \tt{128 \sqrt{2 \: }}}}}}$

Answer 2

Answer:

-140 root 2

Explanation:

answer will be 140 root 2