If x is equal to 3 + root 8 find the value of x square plus 1 by x Square
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x=3+roots 8
1/x=1/3+root 8
1/x=1/3+root8 ×3-root8/3-root8
1/x=3-root8 /(3)^2-(root8)^2
1/x=3-root8 /9-8
1/x=3-root8
x+1/x=3+root8+3-root8 (root 8 will
cancel out)
x+1/x=3+3=6
squaring both sides
(x+1/x)^2=6^2
x^2+(1/x)^2+2×1/x×x=36 (x will cancel out
x^2+(1/x)^2+2×1=36
x^2+*1/x)^2=36-2
=34
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