if x is equal to 7 + 4 root 3 e then the value of 1 by X is
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Answer:
x=(7+4
3
)
2n
x=3+f
f is fractional part of x
⇒0<f<1
Let f
′
=(7−4
3
)
2n
0<7−4
3
<1
0<(7−4
3
)
n
<1
⇒0<f
′
<1
I+f+f
′
=2[
2n
C
0
(7)
2n
+
2n
C
2
(7)
2n−2
+....]
= even
0+f+f
′
<2 is integer.
′
I
′
is integer and f+f
′
is also integer.
⇒f+f
′
=1
f
′
=1−f
x(1−f)=xf
′
=(7+4
3
)
2n
(7−4
3
)
2n
=1
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