if x is equal to cos theta and Y equal to b sin theta then find the value of B Square X square + Y square
Answers
Question
If x is equal to cos theta and y is equal to b sin theta then find the value of b²x² + y².
Answer
b²x² + y² = b²
Solution
Given that, x = cosØ and y = b sin ØWe have to find the value of b²x² + y²
Just simply put the known values.
→ b²x² + y²
→ b²(cos Ø)² + (b sin Ø)²
→ b² cos²Ø + b² sin²Ø
Take b² as common
→ b²(cos²Ø + sin²Ø)
→ b²(1)
→ b²
Used identity is cos²Ø + sin²Ø = 1
Trigonometry formulas
→ sinØ = cos(90° - Ø)
→ secØ = cosec(90° - Ø)
→ tanØ = cot(90° - Ø)
→ sinØ = 1/cosecØ
→ secØ = 1/cosØ
→ tanØ = 1/cotØ
→ sin²Ø + cos²Ø = 1
→ 1 + tan²Ø = sec²Ø
→ 1 + cot²Ø = cosec²Ø
Given :--
- x = cosθ
- y = bsinθ
To Find :--
- (b²x² + y²)
Solution :---
we have to Find value of (b²*x² + y²) ,,Let try to put values ,
→ (b²*x² + y²)
Putting values from given,
→ (b²) * (cosθ)² + (bsinθ)²
→ (b²*cos²θ) + (b²*sin²θ)
Taking b² common now,
→ b²(cos²θ + sin²θ)
Now, we know that, cos²θ + sin²θ = 1.
So,
→ b²(cos²θ + sin²θ)
→ b² * 1