Math, asked by chinu4534, 1 year ago

if x is equal to minus 1 upon 2 is a zero of the polynomial PX is equal to 8 x cube minus a x square - 8 x + 2 find the value of a​

Answers

Answered by kartik2507
1

8 {x}^{3}  - a {x}^{2}  - 8x + 2 \\ x =  -  \frac {1}{2}  \\ substitute \:  -  \frac{1}{2}  \: in \: equation \\ 8 { ( -  \frac{ 1}{2} )}^{3}  - a {( -  \frac{1}{2} )}^{2}  - 8 \times  -  \frac{1}{2}  + 2 \\ 8  \times  -  \frac{1}{8}   +  \frac{a}{4}  + 4 + 2  \\  - 1 +  \frac{a}{4}  + 6 = 0 \\  \frac{a}{4}  + 5 = 0 \\  \frac{a}{4}  =  - 5 \\ a =  - 20

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