Question

If x is equal to minus 2 X square + y square + 3 X y is equal to minus 5 then find

Answer 1

Answer:

incomplete question dear

Answer 2

x = - 5 and y = $\dfrac{15+9\sqrt{5} }{2}$ or, $\dfrac{15-9\sqrt{5} }{2}$

Step-by-step explanation:

We have,

x = $-2x^{2} +y^2+3xy=-5$

To find, the value of x and y = ?

∴ x = $-2x^{2} +y^2+3xy=-5$

⇒ x = - 5 or, $-2x^{2} +y^2+3xy=-5$

∴ $-2x^{2} +y^2+3xy=-5$

Put x = - 5, we get

$-2(-5)^{2} +y^2+3(-5)y=-5$

⇒ $-2(25)+y^2-15y=-5$

⇒ $y^2-15y-45=0$

∴ y $=\dfrac{-b±\sqrt{b^2-4ac} }{2a}$

$=\dfrac{-(-15)±\sqrt{(-15)^2^2-4(1)(-45)} }{2(1)}$

$=\dfrac{15±\sqrt{225+180)} }{2}$

$=\dfrac{15±\sqrt{405} }{2}$

$=\dfrac{15±9\sqrt{5} }{2}$

∴ x = - 5 and y = $\dfrac{15+9\sqrt{5} }{2}$ or, $\dfrac{15-9\sqrt{5} }{2}$