Math, asked by ppiparya, 10 months ago

If x is equal to one is a common root of the equation X square + bx + 3 is equal to zero and X square + X + Q is equal to zero then find the value of p q

Answers

Answered by knjroopa

Step-by-step explanation:

Given If x is equal to one is a common root of the equation X square + bx + 3 is equal to zero and X square + X + Q is equal to zero then find the value of q

Given 1 is root of x^2 + bx + 3 = 0--------1 and

X^2 + bx + q = 0-----------2 has equal roots

Since x = 1 is a root of equation 1 it will satisfy the equation.

Putting x = 1 in eqn 1 we get

1^2 + bx + 3 = 0

1^2 + 1b + 3 = 0

4 + b = 0

So b = - 4

Now putting b = - 4 in equation 2 we get

X^2 + bx + q = 0

X^2 + (-4)x + q = 0

Comparing with ax^2 + bx + c = 0

So a = 1, b = -4, c = ?

We know that

D = b^2 – 4ac

D = (-4)^2 – 4(1)(q)

D = 16 – 4 q

16 – 4 q = 0

16 = 4 q

So q = 16/4 = 4

Therefore the value of q is 4.