if x is equal to root 2 + 1 then find value of x minus one upon x
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Answered by
4
Answer:
x = √2 + 1
x - 1 / x = 0
√2 - 1 - 1 / √2 - 1 = 0
√2 - 2 / √2 - 1 = 0
On rationalizing we get,
2 - √2 - 2√2 + 2 / 2 - 1 = 0
2 - 3√2 + 2 / 1 = 0
4 - 3√2 = 0
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Answered by
0
Answer:
x = root 2+1
=>x-1 =( root 2+1)-1
=>x-1 = x -1
so, value of -x upon x will be -(x-1)
that is -x+1
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