if x is equal to root 3 minus one by root 3 + 1 and y is equal to 3 + 2 root 2 by 3 minus 2 root 2 then find the value of x + y
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X+y=?
(√3-1/√3+1)+(3+2√2/3-2√2)
[(√3-1/√3+1)×(√3-1/√3-1)]+[(3+2√2/3-2√2)×(3+2√2/3+2√2)]
[(√3-1)^2/9-1√3+1√3-1)]+[(3+2√2)^2/9+6√2-6√2-8)]
(^2=square
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