Math, asked by manoj8010156741, 9 months ago

If x is equal to root 3 + root 2 upon root 3 minus root 2 then find X square + 1 upon x square

Answers

Answered by spiderman2019
14

Answer:

98

Step-by-step explanation:

x = √3 + √2 / √3 - √2

  = (√3 + √2) (√3 + √2) / (√3 - √2)(√3 + √2)

  = 3 + 2 + 2√6 / 1 = 5 + 2√6.

1/x  = √3 - √2 / √3 + √2

     = (√3 - √2)(√3 - √2)/ (√3 + √2)(√3 - √2)

     = 3 + 2 - 2√6/1 = 5 - 2√6.

x² + 1/x² = (x + 1/x)² - 2

              = (5 + 2√6 + 5 - 2√6)² - 2

               = (10)² - 2

                = 98.

Answered by bijaymourya8114
18

Step-by-step explanation:

I hope this is helpfull for you

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