If x is equal to root 3 + root 2 upon root 3 minus root 2 then find X square + 1 upon x square
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Answered by
14
Answer:
98
Step-by-step explanation:
x = √3 + √2 / √3 - √2
= (√3 + √2) (√3 + √2) / (√3 - √2)(√3 + √2)
= 3 + 2 + 2√6 / 1 = 5 + 2√6.
1/x = √3 - √2 / √3 + √2
= (√3 - √2)(√3 - √2)/ (√3 + √2)(√3 - √2)
= 3 + 2 - 2√6/1 = 5 - 2√6.
x² + 1/x² = (x + 1/x)² - 2
= (5 + 2√6 + 5 - 2√6)² - 2
= (10)² - 2
= 98.
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18
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