if x is equal to root 5 + 2 root 3 find the value of x square + 1 upon x square
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Answer:
x = √5 + 2√3
1/x = (√5 - 2√3)/( 5 - 12)
= (2√3 -√5)/7
x^2 + 1/x^2 = ( x+1/x)^2 - 2
= (√5 +2√3 + (2√3 -√5)/7)^2 -2
= (7√5 + 14√3 + 2√3 -√5)^2/49 -2
= (6√5 + 16√3)^2/49 -2
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