Question

if x is equal to under root 3 + under root 2 upon under root 3 minus under root 2 and Y is equal to under root 3 minus under root 2 upon under root 3 + under root 2 then find the value of x square+ Y square + x y

Answer 1

Given x = 3 + 2√2
⇒ x = 2 + 1 + 2√2
⇒ x = (√2)2�+ 12�+ 2×√2×1
⇒ x = (√2 + 1)2
∴ x = (√2 + 1)
⇒(1/x) = 1/ (√2 + 1)
Multiply and divide by (√2 − 1)
⇒(1/x) = (√2 − 1) / [(√2 + 1)(√2 − 1)]
⇒(1/x) = (√2 − 1) / [2 − 1]
∴ (1/x) = (√2 − 1)
= 2√2

l hope it helpfull