if x is equals to 1 upon 2 is a zero of polynomial 2 X square + kx - 12 find the value of k
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x=1/2
p(x)=2x^2+kx-12
p(1/2)=2(1/2)^2+k(1/2)-12
0=1/2+1/2k-12
0=(1+k-24)/2
0=-23+k
23=k
k=23
p(x)=2x^2+kx-12
p(1/2)=2(1/2)^2+k(1/2)-12
0=1/2+1/2k-12
0=(1+k-24)/2
0=-23+k
23=k
k=23
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