if X is equals to 2 + root 3 then find x cube + 1 by x cube
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if x=2+√3
then x^3+1/x=2+√3+1/x
=3+√3/x
=(3+√3)(3-√3)/x(3-√3)
=3^2-(√3)^2/3x-√3x
=9-3/3x-√3x
=6/3x-√3x
=6^3/3x-√3x {there was given that x^3}
=216/3x-√3x
you can also solve this by this method if you want
then x^3+1/x=2+√3+1/x
=3+√3/x
=(3+√3)(3-√3)/x(3-√3)
=3^2-(√3)^2/3x-√3x
=9-3/3x-√3x
=6/3x-√3x
=6^3/3x-√3x {there was given that x^3}
=216/3x-√3x
you can also solve this by this method if you want
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Answer:
Hello here's your answer: 61
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