Question

if (x) is equals to 2 + x by 2 + x square minus x cube by 3 then p (- 1) is is​

Answer 1

Answer:

9/4

Step-by-step explanation:

(2+x/2+x^2-x^3/3)*-1

so it will be on solving

9/4

Answer 2

The given question is if (x) is equals to 2 + x by 2 + x square minus x cube by 3 then p (- 1) is is

The given expression is

$p(x) = 2 + \frac{x}{2} + {x}^{2} - \frac{ {x}^{3} }{3} .$

sub x=-1 in the above expressions, we get

$p( - 1) = 2 + \frac{( - 1)}{2} + {( - 1)}^{2} - \frac{ {( - 1)}^{3} }{ 3} \\ = 2 - \frac{1}{2} + 1 + \frac{1}{3} \\ = \frac{12 - 3 + 6 + 2}{6} \\ = \frac{20 - 3}{6} \\ = \frac{17}{6}$

Therefore, the above value is the answer for the given expression.

p(-1) = 17/6.

# spj2

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