if x is equals to 27 by 3 and X is equals to minus 3 are the roots of equation a x square + 7 x + b is equals to zero find the value of AB
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Answer:
according to question,
the roots of this equation are
9 and -3, so,
sum of roots = 9 + (-3) = 6
product of roots = 9 × (-3) = (-27)
so,
-7/a = 6
a = -7/6
and
b/a = (-27)
b/(-7/6) = (-27)
b x (-6/7) = (-27)
b = (-27) ÷ (-6/7)
b = (-27) × (-7/6)
b = -9 × (-7/2)
b = 63/2
ab = (-7/6) x (63/2)
ab = (-7/2) × (21/2)
ab = (-147/4)
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